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Graphing Quadratic Functions Homework Help

A quadratic function y = ax² + bx + c graphs as a parabola, and most homework questions ask for specific features of that curve — its vertex, its axis of symmetry, or which way it opens — rather than a full point-by-point plot.

Common topics

Opening direction

If the coefficient a (in front of x²) is positive, the parabola opens upward and has a minimum point; if a is negative, it opens downward and has a maximum point.

Vertex form

Writing the function as y = a(x - h)² + k puts the vertex directly at the point (h, k) — note again the sign flip on h, exactly as with the circle equation's center.

Axis of symmetry

The vertical line x = h passes through the vertex, and the parabola is a mirror image of itself across this line — useful for finding a second point once one is known.

Finding the vertex from standard form

When the function is given as y = ax² + bx + c, the vertex's x-coordinate is -b / (2a); substitute that value back into the function to get the y-coordinate.

Finding x-intercepts (roots)

The x-intercepts are the points where y = 0, found either by factoring or with the quadratic formula x = (-b ± √(b² - 4ac)) / (2a). The parabola crosses the x-axis at these points, touches it once if there is exactly one root, or never crosses it if the discriminant b² - 4ac is negative.

Worked example

For the function y = 2x² - 8x + 3, find the vertex and state whether it is a minimum or maximum.

  1. Identify a = 2, b = -8, c = 3 from the standard form y = ax² + bx + c.
  2. Find the x-coordinate of the vertex: x = -b / (2a) = -(-8) / (2·2) = 8/4 = 2.
  3. Substitute x = 2 back into the original function to find y: y = 2(2)² - 8(2) + 3 = 8 - 16 + 3 = -5.
  4. Since a = 2 is positive, the parabola opens upward, so the vertex is a minimum.

Answer: Vertex at (2, -5), which is a minimum point, since a = 2 > 0.

Get help with Graphing Quadratic Functions

AI Solve Quiz applies the vertex formula above to a photographed quadratic function and explains why the parabola opens the way it does, instead of only returning the coordinate pair.

Frequently asked questions

Why does the vertex-form formula subtract h instead of add it?
y = a(x - h)² + k is built so the squared term equals zero exactly when x = h — that zero point is what makes (h, k) the vertex. If the formula used (x + h), the vertex's x-coordinate would actually be -h, so always read the sign in front of x carefully.
Do I need to plot every point to graph a parabola for homework?
Usually not — most homework only asks for the vertex, axis of symmetry, and opening direction, plus maybe the y-intercept (found by setting x = 0). Those four features are enough to sketch an accurate parabola without a full table of values.
What does the discriminant tell me before I even solve for the roots?
The discriminant b² - 4ac (the part under the square root in the quadratic formula) tells you how many real x-intercepts exist without solving further: positive means two distinct real roots, zero means exactly one repeated root (the vertex touches the x-axis), and negative means no real roots — the parabola never crosses the x-axis.
How is the vertex related to the x-intercepts?
The vertex's x-coordinate always sits exactly halfway between the two x-intercepts, because a parabola is symmetric across its axis of symmetry. If a homework problem gives both x-intercepts, averaging them is a quick shortcut to the vertex's x-coordinate, without needing the -b/(2a) formula at all.

Related subjects

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